Ml 9600

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Molarity question 10 pts?

How many milliliters of a 1.25 molar hydrochloric acid (HCl) solution would be needed to react completely with 60.0 grams of calcium metal?

Ca (s) + 2HCl (aq) CaCl2 (aq) + H2 (g)

1200 ml

2400 ml

3750 ml

9600 ml

Here's how you should approach this kind of question:

1. Find the number of moles of calcium that you are reacting the HCl with. So, divide 60.0 g by the molar mass of calcium to find the number of moles.

2. The 1.25 molar solution of HCl means there are 1.25 moles per liter of HCl. Take your answer to step 1 and multiply by 2 (the ratio of Ca to HCL is 1:2). This is how many moles of HCl you need.

3. Set up a proportion. If you have an HCl solution that is 1.25 moles per liter, how many liters do you need for (answer to step 2) number of moles?

4. Multiply by 1000 to find the number of liters in milliliters.

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